Solve:

log (5x + 19) = log( 7x + 3)

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Solution

log (5x + 19) = log( 7x + 3)

5x + 19 = 7x + 3

7x - 5x = 19 - 3

2x = 16

x = 8

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Similar questions

Solve:

$l o g_{5} (x + 1) - 1 = 1 + l o g_{5} (x - 1)$

f (x) = {[log (7 x + 3)]}^{5}

x

Solution set of the inequality $l o g_{7} \frac{x - 2}{x - 3} < 0$ is

log 7^{x} = log 9^{x - 2}

2 log 2 x = log (7 x - 2 - {2 x}^{2})

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