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Question

Solve:
3x2+10x+73=0

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Solution

Consider the given quadratic equation.

3x2+10x+73=0

x2+103x+7=0

x2+2×53×x+(53)2253+7=0

(x+53)2=43

x+53=±23

x=3,73

Hence, these are the roots of the given equation.

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