Solve the following
$(a - b + a b) + (b - c + b c) + (c - a + a c)$

Open in App

Solution

$(a - b + a b) + (b - c + b c) + (c - a + a c)$
$= a - b + a b + b - c + b c + c - a + a c$
$= a b + b c + c a$

Suggest Corrections

Similar questions

Q. Solve the following equations :

\frac{x - a b}{a + b} + \frac{x - a c}{a + c} + \frac{x - b c}{b + c}

= a+ b + c

Prove that $∣ ∣ ∣ ∣ ∣ \begin{matrix} a^{2} + 1 & a b & a c a b & b^{2} + 1 & b c a c & b c & c^{2} + 1 \end{matrix} ∣ ∣ ∣ ∣ ∣ = a^{2} + b^{2} + c^{2} + 1$

For a triangle ABC, which of the following is/are true?

Q. Question 8

Sum of

a - b + a b, b + c - b c

and

c - a - a c

is
a)

2 c + a b - a c - b c

2 c - a b - a c - b c

2 c + a b + a c + b c

2 c - a b + a c + b c

Question 10

In $Δ A B C$ ,

a) AB + BC > AC
b) AB + BC < AC
c) AB + AC < BC
d) AC + BC < AB

Join BYJU'S Learning Program

Solve the following(a−b+ab)+(b−c+bc)+(c−a+ac)

(a−b+ab)+(b−c+bc)+(c−a+ac)=a−b+ab+b−c+bc+c−a+ac=ab+bc+ca

Solve the following
$(a - b + a b) + (b - c + b c) + (c - a + a c)$

$(a - b + a b) + (b - c + b c) + (c - a + a c)$
$= a - b + a b + b - c + b c + c - a + a c$
$= a b + b c + c a$