Question

Solve the following equation:
$\frac{3x-1}{4}=11$

Answer 1

Given $\frac{3x-1}{4}=11$
Multiply both sides by $4$, we get:
$$\begin{gathered} \frac{3x-1}{4}\times 4=11\times 4 \\ 3x-1=44 \end{gathered}$$
Transposing $-1$ from L.H.S to R.H.S, we get:
$$\begin{gathered} 3x=44+1 \\ 3x=45 \end{gathered}$$
Dividing both sides by $3$ , we get:
$$\begin{gathered} \frac{3x}{3}=\frac{45}{3} \\ x=15 \end{gathered}$$
Hence the value of $x=15$ is the required solution.