Question

Solve the following equation
$x+3y=62x-3y=12$

Answer 1

Consider the given equation.

$x+3y=6$ …….. (1)

$2x-3y=12$ ……… (2)

On adding both equation (1) and (2), we get

$3x=18$

$x=6$

Now, put the value of $x$ in equation (1), we get

$6+3y=6$

$3y=6-6$

$3y=0$

$y=0$

Hence, the value of $x$ is $6$ and $y$ is $0$.