Solve the following quadratics 21x2−28x+10=0
21x2−28x+10=0We will discriminant rule,x=−b±√D2a ...(A)where D = b24ac=(−28)2−4.21.10=784..840=−56from (A)x=−(−28)±√−562.21=28±2√14i42∴x=23±√1421i
Solve 21x2−28x+10=0
Solve the equation 21x2 – 28x + 10 = 0