Solve: x2−6x+2=0
x2−6x+2=0
Lets compare with ax2+bx+c=0,a≠0
a=1,b=−6,c=2
Roots of the Quadratic equation ax2+bx+c=0,a≠0 are,
x=−b±√b2−4ac2a
⇒x=−(−6)±√(−6)2−4(1)(2)2(1)
⇒x=6±√36−82
⇒x=6±√282
⇒x=6±√4×72
⇒x=6±2√72
⇒x=2(3±√7)2
∴x=3±√7
Solve: a) a)x2+6x=0 b) (x–4)(5x+2)=0 c) x2+3x–18=0