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Question

Solve: x26x+2=0

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Solution

x26x+2=0

Lets compare with ax2+bx+c=0,a0

a=1,b=6,c=2

Roots of the Quadratic equation ax2+bx+c=0,a0 are,

x=b±b24ac2a

x=(6)±(6)24(1)(2)2(1)

x=6±3682

x=6±282

x=6±4×72

x=6±272

x=2(3±7)2

x=3±7


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