Solve::x+2y+z=3, x+2z=8, 3x-2y=8

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$8 (x^{3} y^{2} z^{2} + x^{2} y^{3} z^{2} + x^{2} y^{2} z^{3}) \div 4 x^{2} y^{2} z^{2}$

x + 2 y + z = 8

2 x + 3 y - z = 11

3 x - y - 2 z = 5

x - 2 y + 3 z = 11

3 x + y - z = 2

5 x + 3 y + 2 z = 3

Using matrix method, solve the system of equations 3x + 2y - 2z = 3, x + 2y + 3z = 6 and 2x - y + z = 2.

x + y + 2 z = 4; 2 x + 2 y + 4 z = 8; 3 x + 3 y + 6 z = 12

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