Question

Sort the given numbers in ascending order.

• A. 1315
• B. 1313
• C. 1308
• D. 1304

Answer 1

All are $4$-digit numbers. So, we will compare the place values of all the given numbers to arrange them from the smallest to the highest.


The thousands values are equal to $1$ and the hundreds values are equal to $3$.
So, we will go to the next place.


The tens value for the first, second, third, and fourth numbers are 0, 1, 0, and 1, respectively.

We know that $1>0.$
So, the number with the greater value in the tens place is greater.

Let's compare the numbers with smaller values, i.e., 1308 and 1304.


The ones value for the first number is $8$, and for the second number, it is 4.
Since $8>4$, $1308$ is greater.

∴ $1304<1308$

Now, we will compare the ones place of $1315$ and $1313$.


The ones value for the first number is $5$, and for the second number, it is 3.

Since $5>3$, $1315$ is greater.

∴ $1313<1315$

∴ Arranging the numbers in ascending order, we get:
$1304<1308<1313<1315$