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Question

Solve for the value of x: 3x27x302x27x5=x5

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Solution

3x27x302x27x5=x5

3x27x30=x5+2x27x5

Squaring on both sides,
[3x27x30]2=[x5+2x27x5]2

3x27x30=(x5)2+2x27x5+2(x5)(2x27x5)

3x27x30=x210x+25+2x27x5+2(x5)(2x27x5)

3x27x30=3x217x+20+2(x5)(2x27x5)

7x+17x3020=2(x5)(2x27x5)

10x50=2(x5)(2x27x5)

10(x5)=2(x5)(2x27x5)

5=(2x27x5)

Squaring on both sides
25=2x27x5

2x27x525=0

2x27x30=0

(2x+5)(x6)=0 on factorising

x=52,6

For x=52 the 3x27x302x27x5=x5 equation becomes

3(52)27×52302(52)27×525=525

=754+352302×254+3525

=1451204402

=25420=5245 RHS

x5=525=152

Hence x=52 is not a solution

For x=6 the 3x27x302x27x5=x5 equation becomes

3(6)27×6302(6)27×65=65

=108727247=1

=3625=65=1

Thus, x=6 is the only solution for the above equation

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