-22 equals toA- 2-1-6 B- 2-6 C- 21-6 D- 26

Name: EXEMP - Grade 09 - Mathematics - Number System - Q17
Uploaded: 2022-07-04T10:36:42+05:30
Description: The answer is C. √(√(2)^2) =[√(2)^2]^1/4=[∵√(a)=a^1/n] =[2^2/3]^1/4=2^2/3.1/4 = 2^1/6 nbsp; [(a^m)^n=a^mn] ...

The answer is C. √(√(2)^2) =[√(2)^2]^1/4=[∵√(a)=a^1/n] =[2^2/3]^1/4=2^2/3.1/4 = 2^1/6 nbsp; [(a^m)^n=a^mn] ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Mathematics

Standard Form to Normal Forms

√√22 equals t...

Question

$\sqrt[4]{\sqrt[3]{2^{2}}}$ equals to

A.) $2^{\frac{- 1}{6}}$
B.) $2^{- 6}$
C.) $2^{\frac{1}{6}}$
D.) $2^{6}$

Open in App

Solution

The answer is C.
$\sqrt[4]{{\sqrt[3]{2}}^{2}} = [{\sqrt[3]{2}}^{2}]^{\frac{1}{4}} = [∵ \sqrt[n]{a} = a^{1 / n}]$
$= [2^{2 / 3}]^{1 / 4} = 2^{\frac{2}{3} . \frac{1}{4}} = 2^{\frac{1}{6}} [(a^{m})^{n} = a^{m n}]$

Suggest Corrections

Similar questions

$\sqrt[4]{\sqrt[3]{2^{2}}}$ equals to

A.) $2^{\frac{- 1}{6}}$
B.) $2^{- 6}$
C.) $2^{\frac{1}{6}}$
D.) $2^{6}$

Q. Multiply

(6 k - 1) (k^{2} + 2 k - 4)

If $(a - b) = 6$ and $a^{2} + b^{2} = 30$ , then the value of ab is equal to ____.

Q. The integral

π / 3 \int π / 6 {sec}^{2 / 3} x {c o s e c}^{4 / 3} x d x

is equal to :

Question 22

Which power of 8 is equal to $2^{6}$ ?
(a) 3
(b) 2
(c) 1
(d) 4

Join BYJU'S Learning Program

Explore more

Standard Form to Normal Forms

Standard IX Mathematics

Join BYJU'S Learning Program

4√3√22 equals to A.) 2−16 B.) 2−6 C.) 216 D.) 26

The answer is C. 4√3√22=[3√22]14=[∵n√a=a1/n] =[22/3]1/4=223.14=216 [(am)n=amn]

$\sqrt[4]{\sqrt[3]{2^{2}}}$ equals to

A.) $2^{\frac{- 1}{6}}$
B.) $2^{- 6}$
C.) $2^{\frac{1}{6}}$
D.) $2^{6}$

The answer is C.
$\sqrt[4]{{\sqrt[3]{2}}^{2}} = [{\sqrt[3]{2}}^{2}]^{\frac{1}{4}} = [∵ \sqrt[n]{a} = a^{1 / n}]$
$= [2^{2 / 3}]^{1 / 4} = 2^{\frac{2}{3} . \frac{1}{4}} = 2^{\frac{1}{6}} [(a^{m})^{n} = a^{m n}]$