Question

Square of $\left(\frac{-2}{3}\right)$ is
(a) $-\frac{2}{3}$
(b) $\frac{2}{3}$
(c) $-\frac{4}{9}$
(d) $\frac{4}{9}$

Answer 1

(d) 4/9
To square a number is to raise it to the power of 2. Hence, the square of (−2/3) is
$\frac{(-2{)}^2}{3^2}=\frac{4}{9}$ ---> ( (a/b)ⁿ = (aⁿ)/(bⁿ) )