Square of $3 x - 4 y$ is
a) $9 x^{2} - 16 y^{2}$
b) $6 x^{2} - 8 y^{2}$
c) $9 x^{2} + 16 y^{2} + 24 x y$
d) $9 x^{2} + 16 y^{2} - 24 x y$

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Solution

The correct option is (d) $9 x^{2} + 16 y^{2} - 24 x y$

Given square of $(3 x - 4 y)$ will be $(3 x - 4 y)^{2}$ .
Now, using the identity $(a - b)^{2} = a^{2} - 2 a b + b^{2}$
$(3 x - 4 y)^{2} = (3 x)^{2} - 2.3 x .4 y + (4 y)^{2}$
$= 9 x^{2} - 24 x y + 16 y^{2}$

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Similar questions

3 x - 4 y

9 x^{2} - 16 y^{2}

6 x^{2} - 8 y^{2}

9 x^{2} + 16 y^{2} + 24 x y

9 x^{2} + 16 y^{2} - 24 x y

\frac{9 x^{2} - 24 x y + 16 y^{2}}{3 x - 4 y}

9 x^{2} + 24 x y + 16 y^{2} - 4 y - x + 7 = 0 .

3 x - 4 y = \sqrt{x y}

9 x^{2} + 16 y^{2}

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