Question

Squares of side 2 cm are placed end to end to form rectangles. Match the rectangles to their marked sides.

• A. $12\text{cm}$
• B. $8\text{cm}$
• C. $10\text{cm}$

Answer 1

The length of the above rectangle is equal to the sum of the lengths of the six squares.

The sum of the lengths of the squares is given by

$2\text{cm}+2\text{cm}+2\text{cm}+$
$2\text{cm}+2\text{cm}+2\text{cm}$
$=12\text{cm}.$

$\therefore$ The length of the rectangle is $12\text{cm}.$


Similarly, the breadth of the above rectangle is
$2\text{cm}+2\text{cm}+2\text{cm}+2\text{cm}=8\text{cm}.$


Lastly, the length of the above rectangle is
$2\text{cm}+2\text{cm}+2\text{cm}+2\text{cm}+2\text{cm}$
$=10\text{cm}.$