The correct option is A True
Let p(x)=x3−2x2−x+2
By trial, we find that
p(1)=(1)3−2(1)2−(1)+2
=1−2−1+2=0
∴ By factor Theorem (x-1) is a factor of p(x)
Now, x3−2x2−x+2
=x3−x2−x2+x−2x+2
=x2(x−1)−x(x−1)−2(x−1)
=(x−1)(x2−x−2)
=(x−1)(x2−2x+x−2)
=(x−1){x(x−2)+1(x−2)}
=(x−1)(x−2)(x+1)