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Question

Statement (I): If A+B+C=π(A,B,C>0) and the angle C is obtuse then tanAtanB<1.
Statement (II): If A,B,C are acute positive angles
such that A+B+C=π and cotAcotBcotC=K then
k133 Which of the above statements is correct?

A
Only I
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B
Only II
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C
Both I and II
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D
Neither I nor II
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Solution

The correct option is B Both I and II

Statement I
tan(A+B)=tanA+tanB1tanAtanB
tan(πC)=tanC=tanA+tanB1tanAtanB
C is obtuse angle
tanC is -ve and
A+B is acute angle
tan(A+B) is +ve
tanAtanB<1 True

Statement II
tan(A+B+C)=0, if A+B+C=π
tanA+tanB+tanC=tanAtanBtanC=1k [as given] - 1
By AM-GM on this tanA,tanB,tanC three +ve number
AMGM
tanA+tanB+tanC3(tanAtanBtanC)13
from 1
(tanAtanBtanC)233
tanAtanBtanC33
k133 True.


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