Question 83

Subtract -5308 from the sum [(-2100) +(-2001)].

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Solution

Firstly, we find the sum

(-2100) + (-2001)

= -2100 - 2001

= -4101

Now, subtract -5308 from -4101

-4101 - (-5308)

= -4101 + 5308

=1207

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Subtract the sum of $12 a b - 10 b^{2} - 18 a^{2}$ and $9 a b + 12 b^{2} + 14 a^{2}$ from the sum of $a b + 2 b^{2}$ and $3 b^{2} - a^{2} .$

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