Question

Subtract the sum of '$-9$‘ and ’$-32$‘ from the sum of ’$-13$‘ and ’$-48$'.

Answer 1

Step 1: Find the sum of $-9$ and $-32$:

$\therefore -9+\left(-32\right)=-41$ ($\because$ When we add two negative integers, we add their absolute values and put $-ve$ a sign to their sum)

Step 2: Find the sum of $-13$ and $-48$:

$\therefore -13+\left(-48\right)=-61$ ($\because$ When we add two negative integers, we add their absolute values and put $-ve$ a sign to their sum)

Step 3: Subtract the result of step ($1$) from the result of step ($2$):

$\therefore -61-\left(-41\right)=(-61)+\left(\mathrm{additive}\mathrm{inverse}\mathrm{of}-41\right)$ ($\because$ In subtraction, we add the additive inverse of the number to be subtracted)

$=(-61)+41$

$=-20$ ($\because \left|61\right|>\left|41\right|$, So we shall subtract $41$ from $61$ and will use the sign of $61$)

Therefore, the required answer is $-20$.