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Sulphide lon ...

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Sulphide lon reacts with solid sulphur2$2 (aq)+S(s)S (aq)K, =10S2 (aq)+2S(s) S(aq)KK=130The equilibrium constant for the formation of S-(aq) from S(aq) and sulphur(1) 10(2) 13(3) 130(4) 1300

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Q. Sulphide ion reacts with solid sulphur

S_{(a q)}^{2 -} + S_{(s)} ⇌ S_{2 (a q)}^{2 -}; K_{1} = 10

S_{(a q)}^{2 -} + 2 S_{(s)} ⇌ S_{3 (a q)}^{2 -}; K_{1}^{'} = 130

The equilibrium constant for the formation of

S_{3}^{2 -} (a q)

S_{2}^{2 -} (a q)

and sulphur is:

Sulphide ions in alkaline solution react with solid sulphur to form polyvalent sulphide ions. The equilibrium constant for the formation of $S_{2}^{2 -}$ and $S_{3}^{2 -}$ from S and $S^{2 -}$ ions are 1.7 and 5.3 respectively. Equilibrium constant for the formation of $S_{3}^{- 2}$ from S is:

Q. Sulphide ions in alkaline solution react with solid sulphur to form polyvalent sulphide ions. The equilibrium constant for the formation of

S_{2}^{2 -}

S_{3}^{2 -}

S^{2 -}

ions are 1.7 and 5.3 respectively. Calculate equuilibrium constant for the formation of

S_{3}^{2 -}

S_{2}^{2 -}

S

.

Q. How can be equilibrium concentration of

A g^{+}

can be reduced in a solution of

N a^{+}, C l^{+}, A g^{+}

N O_{3}

, in contact with solid

A g C l

N a^{+} (a q) + C l (a q) + A g^{+} (a q) + N O_{3} (a q) ⇌ A g C l (s) + N a^{+} (a q) + N O_{3} (a q) Δ H = 65.9 k J

Q. The equilibrium constant for the reaction:

F e^{3 +} (a q) + S C N^{-} (a q) ⇌ F e S C N^{2 +} (a q)

is 140 at 298 K.
The Equilibrium constant for the reaction:

2 F e^{3 +} (a q) + 2 S C N^{-} (a q) ⇌ 2 F e S C N^{2 +} (a q)

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