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Question

Sum 12,2,82,.... to 7 terms.

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Solution

The sequence forms a G.P with

a=12 and r=22

Sn=a(1rn1r)S7=121(22)71(22)S7=12(1+105621+22)S7=12(1+105621+22)S7=(1+105622+4)


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