-i-1n 6 i2-a n3-b n2-c n-d- ThenA- a-2B- b-3C- c-2D- d-5

The correct options are A a = 2 B b = 3 ∑_i=1^n 6i^2 = 6∑_i=1^n i^2 = 6n/6 (n+1)(2n+1) = n(2n^2 + 3n + 1) ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

GCD of Polynomials

∑i=1n 6 i2=a ...

Question

$\sum_{i = 1}^{n} 6 i^{2} = a n^{3} + b n^{2} + c n + d$ . Then

a = 2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

b = 3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

c = 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

d = 5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

$\sum_{i = 1}^{n} 6 i^{2} = a n^{3} + b n^{2} + c n + d n$ .Then d =

n \sum s = 1 {s \sum r = 1 r} = a n^{3} + b n^{2} + c n

n \sum r = 1 T_{r} = 5 n + 2

n \sum r = 1 T_{r}^{2} = a n^{3} + b n^{2} + c n + d

d + b + c

{AH}_{2} (g) + {BV}_{2} O_{5} (s) \to {CV}_{2} O_{3} (s) + {DH}_{2} O(l)

n^{t h}

(T_{n})

a n^{3} + b n^{2} + c n + d

T_{n}

Join BYJU'S Learning Program