Sum of factors of $78$ are ________.

168

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170

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167

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189

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Solution

The correct option is A $168$
Factors of $78$ are $1, 2, 3, 6, 13, 26, 39$ and $78$ .
Required sum $= 1 + 2 + 3 + 6 + 13 + 26 + 39 + 78 = 168$ .

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Similar questions

Now look at this problem: the heights of 40 people, in centimeters, are given below. Make a frequency table of this data.

175	143	177	163	170	168	156	168	145	160
159	154	148	166	168	150	164	160	176	163
140	170	165	168	169	174	158	148	155	165
162	167	171	165	171	167	159	171	167	180

Q. Question 4 (i)
The heights of 50 students, measured to the nearest centimeters, have been found to be as follows:

\begin{matrix} 161 & 150 & 154 & 165 & 168 & 161 & 154 & 162 & 150 & 151 162 & 164 & 171 & 165 & 158 & 154 & 156 & 172 & 160 & 170 153 & 159 & 161 & 170 & 162 & 165 & 166 & 168 & 165 & 164 154 & 152 & 153 & 156 & 158 & 162 & 160 & 161 & 173 & 166 161 & 159 & 162 & 167 & 168 & 159 & 158 & 153 & 154 & 159 \end{matrix}

(i) Represent the data given above by a grouped frequency distribution table, taking the class intervals as 160 - 165, 165 - 170, etc.

Question 4 (i)
The heights of 50 students, measured to the nearest centimeters, have been found to be as follows:
$\begin{matrix} 161 & 150 & 154 & 165 & 168 & 161 & 154 & 162 & 150 & 151 162 & 164 & 171 & 165 & 158 & 154 & 156 & 172 & 160 & 170 153 & 159 & 161 & 170 & 162 & 165 & 166 & 168 & 165 & 164 154 & 152 & 153 & 156 & 158 & 162 & 160 & 161 & 173 & 166 161 & 159 & 162 & 167 & 168 & 159 & 158 & 153 & 154 & 159 \end{matrix}$
(i) Represent the data given above by a grouped frequency distribution table, taking the class intervals as 160 - 165, 165 - 170, etc.

Q. The heights of 50 students, measured to the nearest centimetres, have been found to be as follows:

\begin{matrix} 161 & 150 & 154 & 165 & 168 & 161 & 154 & 162 & 150 & 151 162 & 164 & 171 & 165 & 158 & 154 & 156 & 172 & 160 & 170 153 & 159 & 161 & 170 & 162 & 165 & 166 & 168 & 165 & 164 154 & 152 & 153 & 156 & 158 & 162 & 160 & 161 & 173 & 166 161 & 159 & 162 & 167 & 168 & 159 & 158 & 153 & 154 & 159 \end{matrix}

(i) Represent the data given above by a grouped frequency distribution table, taking the class intervals as

160 - 165, 165 - 170,

etc.
(ii) What can you conclude about their heights from the table?

Question 4 (ii)
The heights of 50 students, measured to the nearest centimeters, have been found to be as follows:
$\begin{matrix} 161 & 150 & 154 & 165 & 168 & 161 & 154 & 162 & 150 & 151 162 & 164 & 171 & 165 & 158 & 154 & 156 & 172 & 160 & 170 153 & 159 & 161 & 170 & 162 & 165 & 166 & 168 & 165 & 164 154 & 152 & 153 & 156 & 158 & 162 & 160 & 161 & 173 & 166 161 & 159 & 162 & 167 & 168 & 159 & 158 & 153 & 154 & 159 \end{matrix}$
$\begin{matrix} Height (in cm) & Number of studentss(frequency) 150 - 155 & 12 155 - 160 & 9 160 - 165 & 14 165 - 170 & 10 170 - 175 & 5 Total & 50 \end{matrix}$
(ii) What can you conclude about their heights from the table?

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175	143	177	163	170	168	156	168	145	160
159	154	148	166	168	150	164	160	176	163
140	170	165	168	169	174	158	148	155	165
162	167	171	165	171	167	159	171	167	180

175	143	177	163	170	168	156	168	145	160
159	154	148	166	168	150	164	160	176	163
140	170	165	168	169	174	158	148	155	165
162	167	171	165	171	167	159	171	167	180

Sum of factors of 78 are ________.

The correct option is A 168Factors of 78 are 1,2,3,6,13,26,39 and 78.Required sum =1+2+3+6+13+26+39+78=168.

Sum of factors of $78$ are ________.

The correct option is A $168$
Factors of $78$ are $1, 2, 3, 6, 13, 26, 39$ and $78$ .
Required sum $= 1 + 2 + 3 + 6 + 13 + 26 + 39 + 78 = 168$ .

175	143	177	163	170	168	156	168	145	160
159	154	148	166	168	150	164	160	176	163
140	170	165	168	169	174	158	148	155	165
162	167	171	165	171	167	159	171	167	180