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Question

Suppose a,b,cϵR, a+b+c> 0, A=bca2, B=cab2, C=abc2
and ∣ ∣ABCBCACAB∣ ∣=49

then ∣ ∣abcbcacab∣ ∣ equals :

A
7
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B
2401
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C
2401
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D
7
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Solution

The correct option is A 7
For ∣ ∣abcbcacab∣ ∣
∣ ∣c11c12c13c21c22c23c31c32c33∣ ∣=∣ ∣ABCBCACAB∣ ∣
Then ∣ ∣abcbcacab∣ ∣=7

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