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General Solutions of (sin theta)^2 = (sin alpha)^2 , (cos theta)^2 = (cos alpha)^2 , (tan theta)^2 = (tan alpha)^2

Tan^-1(tan(-6...

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Tan^-1(tan(-6))

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{tan}^{- 1} (tan (- 6)) .

If $A = [\begin{matrix} 1 & t a n x - t a n x & 1 \end{matrix}], A^{T} A^{- 1} =$ ___

\int \tan^{- 1} \sqrt{x} d x i s e q u a l t o (a) (x + 1) \tan^{- 1} \sqrt{x} - \sqrt{x} + C (b) x \tan^{- 1} \sqrt{x} - \sqrt{x} + C (c) \sqrt{x} - x \tan^{- 1} \sqrt{x} + C (d) \sqrt{x} - (x + 1) \tan^{- 1} \sqrt{x} + C

If u = \cot^{- 1} \sqrt{\tan θ} - \tan^{- 1} \sqrt{\tan θ} then, \tan (\frac{π}{4} - \frac{u}{2}) =

\sqrt{\tan θ}

\sqrt{\cot θ}

cos [{cos}^{- 1} cos [\frac{8 π}{7}] + {tan}^{- 1} tan [\frac{8 π}{7}]]

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