Factorise: x2+6x+9−x−3
(x+2)(x+3)
We need to factorise the givenexpression:
x2+6x+9−x−3
Consider the first three terms of thegiven expression: x2+6x+9.
On comparing x2+6x+9 with the identity (a+b)2=a2+2ab+b2,we get, x2+6x+9=(x+3)2.
Hence, x2+6x+9−x−3=(x+3)2−x−3=(x+3)(x+3)−1(x+3)
Taking (x+3) common , we get
(x+3)((x+3)−1)=(x+3)(x+2)
Thus, x2+6x+9−x−3=(x+3)(x+2)