If m - 1-5-26 then- m2 - -3 marks

M = 1/5+√(26) m = 1/5+√(26)×5 √(26)/5 √(26) =5 √(26)/(5)^2 (√(26))^2 nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp ...

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Properties of Conjugate of a Complex Number

If m = 1/5+√2...

Question

$If m = \frac{1}{5 + \sqrt{26}} then, m^{2} =$ _______.

(3 marks)

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If m = \frac{1}{5 + \sqrt{26}} then, m^{2} =

$If m = \frac{1}{3 - 2 \sqrt{2}} then, m^{2} =$ _______.

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$2 m n^{2} - 15 m^{2} n + p$

m = max {∣ ∣ | x - 5 | - | x - 3 | ∣ ∣}

n = min {∣ ∣ x - 2 | + | x - 4 |},

m + n

If $m$ and $σ^{2}$ are the mean and variance of variable $X$ , whose distribution is given by:

$X$	$0$	$1$	$2$	$3$
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Then:

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