What is the value of "a" if the value of the expression 3 $x^{2}$ + 6a+ 2 is 29 when x=1 ?

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Solution

The correct option is D
4

3 $x^{2}$ + 6a+ 2 = 29

$3 \times 1^{2}$ + 6a + 2 = 29

$3 \times 1$ + 6a + 2 = 29

=> 3 + 6a + 2 = 29

=> 5 + 6a = 29

=> 6a = 24

=> $a = \frac{24}{6}$

=> a= 4

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