1
Question
Solve for x.
15−2(5−3x)=4(x−3)+13
Solve for x.
15−2(5−3x)=4(x−3)+13
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Solution
The correct option is A -2
Given,
15−2(5−3x)=4(x−3)+13⇒15−10+6x=4x−12+13⇒5+6x=4x+1
Transposing 4x from RHS to LHS and transposing 5 from LHS to RHS, we get,
6x−4x=1−5⇒2x=−4⇒x=−2
-2
Given,
15−2(5−3x)=4(x−3)+13⇒15−10+6x=4x−12+13⇒5+6x=4x+1
Transposing 4x from RHS to LHS and transposing 5 from LHS to RHS, we get,
6x−4x=1−5⇒2x=−4⇒x=−2
Suggest Corrections
2
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