Question

$\text{Solve for x:}$
$6(x+5)–4(x+1)=9(x+3)$

• A. $-\frac{2}{7}$
• B. $-\frac{1}{7}$
• C. 7
• D. $-\frac{5}{7}$

Answer 1

The correct option is B

$-\frac{1}{7}$

$6(x+5)–4(x+1)=9(x+3)$

Simplifying both sides of the equation, we get
$6x+30–4x-4=9x+27$
$\Rightarrow 2x+26=9x+27$

Transposing 9x from RHS to LHS, and 26 from LHS to RHS, we get,
$\Rightarrow 2x-9x=27-26\Rightarrow -7x=1$

Transposing -7 from LHS to RHS, we get
$x=\frac{1}{-7}=-\frac{1}{7}$