Solve for x-x-a-x-b-1A- a-b-a ba-bB- a-b-bbC- u-a-bD- a b-a-b

The correct option is D ab/a+bx/a+x/b=1 ⇒bx+ax/ab=1 ⇒x(a+b)/ab=1 Transposing ab to the RHS, we get x(a+b)=ab Transposing (a+b) to the RHS, we get x=ab/a+ ...

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Standard VIII

Mathematics

Equations Reducible to the Linear Form

Solve for x:x...

Question

$Solve for x:$

$\frac{x}{a} + \frac{x}{b} = 1$

\frac{(a + b)}{b}

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\frac{(a + b)}{a b}

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\frac{b}{a + b}

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\frac{a b}{a + b}

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Solution

The correct option is D $\frac{a b}{a + b}$
$\frac{x}{a} + \frac{x}{b} = 1 \Rightarrow \frac{b x + a x}{a b} = 1 \Rightarrow \frac{x (a + b)}{a b} = 1 Transposing ab to the RHS, we get x (a + b) = a b Transposing (a+b) to the RHS, we get x = \frac{a b}{a + b}$

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Similar questions

Q. Solve for

x : \frac{1}{(a + b + x)} = \frac{1}{a} + \frac{1}{b} + \frac{1}{x}, [a \neq 0, b \neq 0, x \neq 0, x \neq - (a + b)]

The lowest form of $\frac{(a + b)}{a b} - \frac{2}{(a + b)}$ if ab=1.

Q. Solve for x and y:

a x - b y = a^{2} + b^{2}, x + y = 2 a

Q. If A = {x : x is a multiple of 3} and , B = {x : x is a multiple of 5}, then A − B is
(a)

A \cap B

(b)

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(c)

A \cap B

(d)

A \cap B

If A = {x : x is a multiple of 3} and , B = {x :x is a multiple of 5}, then A - B is

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Solve for x: xa+xb=1

The correct option is D aba+bxa+xb=1⇒bx+axab=1⇒x(a+b)ab=1Transposing ab to the RHS, we get x(a+b)=abTransposing (a+b) to the RHS, we get x=aba+b

$Solve for x:$

$\frac{x}{a} + \frac{x}{b} = 1$

The correct option is D $\frac{a b}{a + b}$
$\frac{x}{a} + \frac{x}{b} = 1 \Rightarrow \frac{b x + a x}{a b} = 1 \Rightarrow \frac{x (a + b)}{a b} = 1 Transposing ab to the RHS, we get x (a + b) = a b Transposing (a+b) to the RHS, we get x = \frac{a b}{a + b}$