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Question

The following data applies to the basic shaft system

Tolerance for hole = 0.002 mm,

Tolerance for shaft = 0.001 mm,

Allowance = 0.003 mm, Basic size = 50 mm

The maximum hole size is mm(round off to 3 decimal places)
  1. 50.005

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Solution

The correct option is A 50.005
Given data:

Tolerance for hole = 0.002 mm,

Tolerance for shaft = 0.001 mm,

Allowance = 0.003 mm, Basic size = 50 mm

Using diagram method


UL of hole = BS+0.003+0.002 mm = 50.005 mm

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