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Question

The message bit sequence to a DPSK modulator is "1, 0. 1, 1, 0". This data is differentially encoded with unknown logic gate (EX-OR/EX-NOR) and unknown starting reference bit. Carrier phase of "π" is assigned to logic - 0 and carrier phase of "0" is assigned to logic - 1 after encoding the data. If the carrier phase corresponding to the first two message bits (from left side) are ,π 0 respectively, then the carrier phases corresponding to the remaining three message bits will be respectively

A
0,π,π
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B
0,0,π
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C
π,π,0
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D
π,π,0
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Solution

The correct option is B 0,0,π
It is given that the carrier phase for first two encoded bits areπ,0. So first two encoded bits are 0,1.
The logic diagram of DPSK encoder can be given as,

Finding the logic gate:

If we observe clearly,

d0(logic) b1=d1
0(logic) 0=1

So the possible logic is, EX-NOR.
So, the complete encoding can be given as,

So, the carrier phases corresponding to the remaining three bits are 0,0,π

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