$\int_{- 1}^{1} x | x | d x =$ [MP PET 1990; Pb. CET 2004]

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Solution

The correct option is B \N
$L e t f (x) = x | x | . T h e n f (- x) = - x | - x | = - x | x | = - f (x)$
Therefore $\int_{- 1}^{1} x | x | d x = 0$
(By the property of definite integral).

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