Question

The 4 term of a H.P is $\frac{3}{5}$ and 8th term is $\frac{1}{3}$, then its 6th term is

• A.
• B.
• C.
• D.

Answer 1

The correct option is B

a + 3d = $\frac{5}{3}$ and a + 7d = 3

Solving a = $\frac{2}{3}$, d = $\frac{1}{3}$

6th term of A.P = a + 5d = $\frac{2}{3}+\frac{5}{3}$ = $\frac{7}{3}$

$\Rightarrow$ 6th term of H.P. = $\frac{3}{7}$.