The correct option is B
3,6,12,24,...
Let first term be a and common ratio be 'r'
a5=ar4, a8=a.r7a8a5=38448⇒a.r7a.r4=38448⇒r=3√8=2a5=48⇒a.r4=48⇒a.(2)4=48⇒16a=48∴ a=3a1=a=3a2=ar=3×2=6a3=ar2=3×22=12a4=ar3=3×23=24The required GP is 3,6,12,24...
Hence, option b is correct.