The correct option is B π2
Let l1,m1,n1 be D.R.’s of the line
x + y – 2z = 0 = 3x + 2y + z
⇒l1+m1−2n1=0
⇒3l1+2m1+n1=0⇒l15=m1−7=n1−1.....(1)
Let l2,m2,n2 be D.R.’s of the line
2x – y – z = 0 = 7x + 10y – 8z
⇒2l2−m2−n2=0
7l2+10m2−8n2=0
⇒l218=m29=n227
i.e., l22=m21=n23....(2)
Let θ be angle between two lines. Then
cosθ=10−7−3√4+1+9√25+49+1=0⇒θ=π2