Question

The antilog of $\left(1.32\right)$ is equal to

• A. $20$
• B. $20.98$
• C. $20.89$
• D. $20.79$

Answer 1

Answer: (C)

$20.89$

The number before decimal point is $1,$ so decimal point will be after $2$ digits.

Value of $1.32$ from antilog table $=2089$

Now place a decimal point after $2$ digits of the number from left we get, $20.89$

Antilog $1.32=20.89$

Hence, C is the correct option.