The area of a circle can be visualised by dividing the circle into equal sectors, and rearranging the sectors to form a __. The area of the rearranged figure will be equal to the area of the circle.

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Solution

The rearranged figure can be visualised as a rectangle with base equal to half the circumference of the circle (πr) and the width as the radius (r)

The area of the rectangle is equal to $π r \times r = π r^{2}$ which is the area of the circle

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The area of a circle can be visualised by dividing the circle into equal sectors, and rearranging the sectors to form a __. The area of the rearranged figure will be equal to the area of the circle.

The rearranged figure can be visualised as a rectangle with base equal to half the circumference of the circle (πr) and the width as the radius (r) The area of the rectangle is equal to πr×r=πr2 which is the area of the circle

The rearranged figure can be visualised as a rectangle with base equal to half the circumference of the circle (πr) and the width as the radius (r)

The area of the rectangle is equal to $π r \times r = π r^{2}$ which is the area of the circle