Question

The area of the given figure will be

• A. $60sq.units$
• B. $72sq.units$
• C. $66sq.units$
• D. $96sq.units$

Answer 1

The correct option is C

$66sq.units$

The area of the figure is the sum of areas of all rectangles and squares contributing to the figure.
$\therefore$ Area = $\text{3}\times \text{4 + 3}\times \text{4 + 3}\times \text{4 + 3}\times \text{7 + 3}\times \text{3}$
= $12+12+12+21+9$
= $66sq.units$