Question

The articles of a $△$ are A(-1,-7) ,B(5,1) and C(1,4) . IT internal angle bisector of angle B meet side AC at D . Then find length AB.

Answer 1

We have,

$A(x_1,y_1)=(-1,1)$

$B(x_2,y_2)=(5,1)$

$C(x_3,y_3)=(1,4)$

Now, we know that,

$AB=\sqrt{{(x_2-x_1)}^2+{(y_2-y_1)}^2}$

$=\sqrt{{(5+1)}^2+{(1+7)}^2}$

$=\sqrt{36+64}$

$=\sqrt{100}$

$=10unit.$

Hence, the length of $AB=10unit$

This is the answer.