Question

The base and top radius of a cone is $2.1$ m and $0.8$ m respectively. The height of the cone is $24$ m. What is the volume of frustum of a cone? (Use $\pi =3.14$). Insert answer in nearest integer,

Answer 1

Volume of the frustum cone = $\frac{1}{3}\pi h(R^2+r^2+Rr)$
$=\frac{1}{3}\pi \times 24({2.1}^2+{0.8}^2+1.68)$
$=\frac{1}{3}\pi \times 161.52$
$=\frac{1}{3}\times 3.14\times 161.52$
$=169.05m^3$