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Question

The ∣ ∣abcc+ba+cbcaabb+ac∣ ∣ is equal to

A
abc(a2+b2+c2)
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B
(a+b+c)(a2+b2+c2)
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C
(a+b+c)2(a2+b2+c2)
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D
abc
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Solution

The correct option is C (a+b+c)(a2+b2+c2)
∣ ∣abcc+ba+cbcaabb+ac∣ ∣
C1aC1
=1a∣ ∣ ∣a2bcc+ba2+acbcaa2abb+ac∣ ∣ ∣
C1C1+bC2+cC3
=1a∣ ∣ ∣a2+b2+c2bcc+ba2+b2+c2bcaa2+b2+c2b+ac∣ ∣ ∣
=a2+b2+c2a∣ ∣1bcc+b1bca1b+ac∣ ∣
R2R2R1,R3R3R1
=a2+b2+c2a∣ ∣1bcc+b0c(a+b)0a+cb∣ ∣
=a2+b2+c2a[bc+a2+ac+bc+ab]
=(a+b+c)(a2+b2+c2)

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