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the chemical reaction 2O3 →3O2 proceeds as follows O3→ O2 +O (FAST) O+O3→2O2 (SLOW) the rate law expression should be

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Q. The chemical reaction,

2 O_{3} \to 3 O_{2}

proceeds as follows;

O_{3} ⇌ O_{2} + O

O + O_{3} \to 2 O_{2}

....(Slow)
The rate law expression should be:

Q. For the chemical reaction,

2 O_{3} \to 3 O_{2}

proceed as follows

O_{3} ⇌ O_{2} + O . . . . . (f a s t)

O + O_{2} \to 2 O_{2} . . . . . (s l o w)

The rate law expression will be:

Q. The chemical reaction

{2 O}_{3} ⟶ {3 O}_{2}

proceeds as follows

O_{3} ⇌ O_{2} + O

O + O_{3} ⇌ {2 O}_{2}

......(slow)
The rate of expression should be

Q. For the chemical reaction,

2 O_{3} ⇌ 3 O_{2}

The reactions proceed as follows

O_{3} ⇌ O_{2} + O

O + O_{2} \to 2 O_{2}

(slow)
The rate law expression will be:

Q. The chemical reaction ,

2 O_{3} \to 3 O_{2}

proceeds as follows:

O_{3} ⇌ O_{2} + O

.......... (fast)
Step2:

O + O_{3} \to 2 O_{2}

............... (slow)

The rate law expression should be:

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