The concentration of NH-4OH in 0-18 M aqueous ammonium acetate solution will be Given- K-a-CH-3COOH-K-b-NH-4OH-1-8-10-5-1- 10-3M -2- 10-4M -3- 4-10-3M -4- 6-10-5 M

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Physical Properties (Group 1)

The concentra...

Question

The concentration of NH_4OH in 0.18 M aqueous ammonium acetate solution will be \lbrack Given: K_a(CH_3COOH)=K_b(NH_4OH)=1.8×10^{-5}\rbrack (1) 10^{-3}M (2) 10^{-4}M (3) 4×10^{-3}M (4) 6×10^{-5 }M

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0.05

0.001

O H^{-}

K_{b} (N H_{4} O H) = 1.8 \times 10^{- 5}

0.05

0.001

O H^{-}

K_{b} (N H_{4} O H) = 1.8 \times 10^{- 5}

H^{+}

(K_{a} = 1.8 \times 10^{- 5}, K_{b} = 1.8 \times 10^{- 5}, K_{w} = 1.0 \times 10^{- 14})

C H_{3} C O O H

0.01

C H_{3} C O O^{-} N H_{4}^{+}

1 L

H_{2} O

[K_{a (C H_{3} C O O H)} = 1.8 \times 10^{- 5}; K_{b (N H_{4} O H)} = 1.8 \times 10^{- 5}]

K_{a}

C H_{3} C O O H

1.8 \times 10^{- 5}

K_{b}

N H_{4} O H

1.8 \times 10^{- 5}

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