Question

The Crystal Field Stabilization Energy (CFSE) of $\left[{\mathrm{CoF}}_3{\left({\mathrm{H}}_2\mathrm{O}\right)}_3\right]({\mathrm{\Delta }}_0<\mathrm{P})$is:

• A. $–0.8{∆}_0$
• B. $–0.8{\mathrm{\Delta }}_0+2\mathrm{P}$
• C. $–0.4{\mathrm{\Delta }}_0+\mathrm{P}$
• D. $–0.4{∆}_0$

Answer 1

The correct option is D

$–0.4{∆}_0$

The correct option is (D):

Explanation for the correct answer:

Crystal field stabilization energy:

1. This energy basically refers to the energy difference between the energy of the electron configuration of the ligand and the energy of electron configuration of the isotropic field.
2. When there is the presence of the weak field ligand then it will cause the low difference between the lower and the higher energy level orbitals.
3. As $\left[{\mathrm{CoF}}_3{\left({\mathrm{H}}_2\mathrm{O}\right)}_3\right]({\mathrm{\Delta }}_0<\mathrm{P})$ is there, which means there is the presence of weak field ligands.
4. So,
5. Hence, $[-0.4\times 4+0.6\times 2]{∆}_0$ = $[-0.4{∆}_0]$

Therefore, the correct answer is (D):- $–0.4{∆}_0$.