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Question

The cubic polynomial p(x) satisfies p(0)=1, p(1)=20, p(2)=40, p(3)=60. Then the value of p(4) is

A
78
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B
79
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C
80
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D
81
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Solution

The correct option is B 79
p(x)=λ(x1)(x2)(x3)+20xp(0)=1λ=16p(x)=16(x1)(x2)(x3)+20xp(4)=1+80=79

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