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B
O−2
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C
O2
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D
O2−2
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Solution
The correct option is DO2−2 The molecular orbital diagram of O2 is,
The species will be diamagnetic if there is no unpaired electron present. In O+2 , one unpaired electron will be there. In O−2 also one unpaired electron will be there. In O2 , two unpaired electron will be there. But, in O2−2 no unpaired electron is present, so it will be diamagnetic in nature.