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Standard XII

Mathematics

Distance Formula

The distance ...

Question

The distance between $(4, 3)$ and $(5, 9)$ is

\sqrt{37} units

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\sqrt{35} units

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5 units

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6 units

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Solution

The correct option is A $\sqrt{37} units$
Using distance formula
$d = \sqrt{(x_{1} - x_{2})^{2} + (y_{1} - y_{2})^{2}} \Rightarrow d = \sqrt{(4 - 5)^{2} + (3 - 9)^{2}} \Rightarrow d = \sqrt{1 + 36} = \sqrt{37} units$

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Distance Formula

Standard XII Mathematics

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The distance between (4,3) and (5,9) is

The correct option is A √37 units Using distance formula d=√(x1−x2)2+(y1−y2)2⇒d=√(4−5)2+(3−9)2⇒d=√1+36=√37 units

The distance between $(4, 3)$ and $(5, 9)$ is

The correct option is A $\sqrt{37} units$
Using distance formula
$d = \sqrt{(x_{1} - x_{2})^{2} + (y_{1} - y_{2})^{2}} \Rightarrow d = \sqrt{(4 - 5)^{2} + (3 - 9)^{2}} \Rightarrow d = \sqrt{1 + 36} = \sqrt{37} units$