Question

The distance between $(4,3)$ and $(5,9)$ is

• A. $\sqrt{37}\text{units}$
• B. $\sqrt{35}\text{units}$
• C. $5\text{units}$
• D. $6\text{units}$

Answer 1

The correct option is A $\sqrt{37}\text{units}$

Using distance formula
$d=\sqrt{(x_1-x_2{)}^2+(y_1-y_2{)}^2}\Rightarrow d=\sqrt{(4-5{)}^2+(3-9{)}^2}\Rightarrow d=\sqrt{1+36}=\sqrt{37}\text{units}$