The distance between the plates of a parallel plate air condenser is d. if a copper plate of the same area but thickness $\frac{d}{2}$ is placed between the plates then the new capacitance will become :

doubled

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half

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one fourth

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remain unchanged

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Solution

The correct option is A doubled
Capacitance of parallel plate capacitor is $C = \frac{A ϵ}{d}$
If distance between plate is $d / 2$
so new capacitance is $C^{'} = \frac{A ϵ}{d / 2} = 2 \frac{A ϵ}{d} = 2 C$

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The distance between the plates of a parallel plate air condenser is d. if a copper plate of the same area but thickness d2 is placed between the plates then the new capacitance will become :

The correct option is A doubledCapacitance of parallel plate capacitor is C=AϵdIf distance between plate is d/2so new capacitance is C′=Aϵd/2=2Aϵd=2C

The distance between the plates of a parallel plate air condenser is d. if a copper plate of the same area but thickness $\frac{d}{2}$ is placed between the plates then the new capacitance will become :

The correct option is A doubled
Capacitance of parallel plate capacitor is $C = \frac{A ϵ}{d}$
If distance between plate is $d / 2$
so new capacitance is $C^{'} = \frac{A ϵ}{d / 2} = 2 \frac{A ϵ}{d} = 2 C$