The elevator shown in figure is descending with an acceleration of 2m/s2. The mass of the block A is 0.5 kg. What force is exerted by the block a on the block B ?
From the free bosy diagram
R=0.5×2−W=0
⇒R=W−0.5×2
= 0.5×10−0.5×2
= 0.5(10-2) = 4 N
So , the force exerted by the block A on the block B is 4N.