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Question

The elevator shown in figure is descending with an acceleration of 2m/s2. The mass of the block A is 0.5 kg. What force is exerted by the block a on the block B ?


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Solution

From the free bosy diagram

R=0.5×2W=0

R=W0.5×2

= 0.5×100.5×2

= 0.5(10-2) = 4 N

So , the force exerted by the block A on the block B is 4N.


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